Question

Diagnoals AC and BD of a quadrilateral ABCD intersect each other at P. Show that. ar(APB) × ar(CPD=ar(APD) × ar(BPC).

Answer 1

Diagonals AC and BD of a quadrilateral ABCD intersect at P. show that ar(APB)×ar(CPD) = ar(BPC)×ar(APD)