Question

Diagonal AC =4.4cm , diagonal BD = 6.8cm, and the angle between the diagonals = 60°. Construct a parallelogram​

Answer 1

Answer:

hey here is your answer

STEP 1: At first draw the diagonal AC of 3.8 cm.

STEP 2: Now from the centre of AC (let M), draw a perpendicular line.

STEP 3: From C draw a 600 angle downward with the help of protractor. The intersection point between the line and the perpendicular is B.

STEP 4: From B draw an arc of radius 4.6 cm on the perpendicular line. The intersecting point is D. Join AD, CD and AB.

hope it help u

Answer 2

Given, ABCD is a rectangle

We know that the diagonals of rectangle are same and bisect each other

So, we have

AP = BP

∠PAB = ∠PBA (Equal sides have equal opposite angles)

∠PAB = 50o (Since, given ∠PBA = 50o)

Now, in ∆APB

∠APB + ∠ABP + ∠BAP = 180o

∠APB + 50o + 50o = 180o

∠APB = 180o – 100o

∠APB = 80o

Then,

∠DPB = ∠APB (Vertically opposite angles)

Hence,

∠DPB = 80o