Diagonal AC and BD of a parallelogram ABCD intersect at O if BOC is equal to 90 degree and BDC is equal to 50 degree find OAB
Answers
Answered by
16
Step-by-step explanation:
ABCD is a //gm
Since, AB//CD
angle BDC=angle ABD
Angle ABD=50°
Then,
angle BOC+angleAOB=180°
=)90°+angle AOB=180°
=)angleAOB=90°
Now,
In triangle AOB,
=)50°+90°+angle OAB=180°
=)angle OAB=180°-140°
Hence, angle OAB=40°
Hope it helps u.
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Answered by
2
Oab = 40 degree
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