diagonal AC and BD of a quadrilateral ABCD intersects each other at 0. prove that AB+BC+CD+DA>AC+BD and AB+BC+CD+Da<2(AC+BD).
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HEY DUDE.. HERE IS THE SECOND ANSWER
IN THE FIRST ONE U HAVE MENTIONED THAT DIAGONALS INTERSECT AT O IF O WOULDN'T BE THERE THEN I WILL BE ABLE TO GIVE THE ANSWER OF THE FIRST ONE..
IN THE FIRST ONE U HAVE MENTIONED THAT DIAGONALS INTERSECT AT O IF O WOULDN'T BE THERE THEN I WILL BE ABLE TO GIVE THE ANSWER OF THE FIRST ONE..
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2Shashank1111:
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Dear\(-ㅂ-)/ ♥ ♥ ♥
thnx
Hii.
Nice to meet u
nice to meet you too
Ur introduction
Myself Shashank from Lucknow n u
This is Geneva from Manipur
but I actually live in Delhi
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Hope it helps you
♡Thank you♡
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