diagonal AC and BD of a Trapezium ABCD with ab parallel DC intersect each other at point O using similar Criterion of two Triangles show that OA/OC*OB/OD=1
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Given: ABCD is a trapezium in which AB is parallel to DC
To Prove: OA/OC = OB /OD
Proof: In tr. OAB and tr. ODC,
Given: ABCD is a trapezium in which AB is parallel to DC
To Prove: OA/OC = OB /OD
Proof: In tr. OAB and tr. ODC,
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