Question

diagonal AC and BD of quadrilateral ABCD intersect at O such that OB=OD. Then prove that ar(DAC)=ar(BCA)?

Answer 1

As o is the mid point of BD
so,OA is the median
= ar(AOD)=at(BoA) -(1)
same as OC is the median
=ar(DOC)-ar(BOC)_ (2)
on adding equations 1 and 2
as ar DAC - ar( BAC)