Diagonal AC of a parallelogram ABCD bisects Angle A, show that It Bisects Angle C also. Show that parallelogram ABCD Is a rhombus
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Solution: Given: The diagonal AC of a parallelogram ABCD bisects ∠A. We can use alternate interior angles property to show that the diagonal AC bisects ∠C and by showing all sides are equal, it can be proved ABCD is a rhombus. ... Hence, ABCD is a rhombus
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