Diagonal AC of a parallelogram ABCD bisects angleA. show that:
(i) it bisects angleC also
(ii)ABCD is rhombus
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HEY.....
HERE IS UR ANSWER...
ABCD IS A PARALLELOGRAM
THEREFORE ANGLE DCA = ANGLE CAM AND
ANGLE DAC = ANGLE ACB
[ ALTERNATE ANGLES]
BUT ANGLE DAC = ANGLE CAB
THEREFORE ANGLE DCA = ACB
SO AC BISECT ANGLE C ALSO..
NOW ANGLE CAB = DCA AND
ANGLE CAM =DAC
THEREFORE ANGLE DCA = ANGLE DAC
SIDES OPP. TO EQUAL ANGLES ARE EQUAL ...
THEREFORE AD= DC
NOW IF IN A PARALLELOGRAM ADJACENT SIDES ARE EQUAL THEN IT IS RHOMBUS...
HERE IS UR ANSWER...
ABCD IS A PARALLELOGRAM
THEREFORE ANGLE DCA = ANGLE CAM AND
ANGLE DAC = ANGLE ACB
[ ALTERNATE ANGLES]
BUT ANGLE DAC = ANGLE CAB
THEREFORE ANGLE DCA = ACB
SO AC BISECT ANGLE C ALSO..
NOW ANGLE CAB = DCA AND
ANGLE CAM =DAC
THEREFORE ANGLE DCA = ANGLE DAC
SIDES OPP. TO EQUAL ANGLES ARE EQUAL ...
THEREFORE AD= DC
NOW IF IN A PARALLELOGRAM ADJACENT SIDES ARE EQUAL THEN IT IS RHOMBUS...
anu522:
PLZ MRK BRAINLIEST
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