Question

Diagonal AC of a parallelogram is joined as shown in the adjoining figure show that triangle ABC congruent to triangle CDA

Answer 1

Here's Ur answer..

In ∆ABC and ∆CDA

AC=AC(common)

AB=DC(opp. side of llgm)

BC=AD(opp.side of llgm)

∆ABC congruent to ∆CDA(SSS)

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