diagonal of a parallelogram bisects each other
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The diagonals of a parallelogram bisect each other. ... In any parallelogram, the diagonals (lines linking opposite corners) bisect each other. That is, each diagonal cuts the other into two equal parts. In the figure above drag any vertex to reshape the parallelogram and convince your self this is so.
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The diagonals of a parallelogram bisects each other.
Given: ABCD is a parallelogram with AC and BD diagonals & O is the point of intersection of AC and BD.
To prove: OA = OC & OB = OD
_______________________________
Prove :
since, opposite sides of parallelogram are parallel.
AD || BC I AD || BC
with transversal BD l with transversal AC
/_ ODA = /_ OBC l /_ ODA = /_ DCB
(alternate interior l (alternate interior
angles) l angles)
________________________________
In ∆ AOD & ∆ BOC
/_ OAD = /_ OCB | from (1) |
AD = CB | opposite sides of
parallelogram are equal |
/_ ODA = /_ OBC | from (2) |
∆ AOD = ∆ BOC | ASA rule |
So,
OA = OC & OB = OD | CPCT |
Hence proved.
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