Question

diagonal of a parallelogram divides it into two congruent

triangles.​

Answer 1

Answer:

• for figure refer to attachment.

Step-by-step explanation:

To prove :

△ABD ≅ △CBD

Proof :

AB ∥ DC

=> ∠1 = ∠2 & ∠3 = ∠4 ( alternate interior angles.)

In △ABD and △CBD

∠1 = ∠2 ( proved above)

∠ 3 = ∠4 ( proved above)

BD = BD ( common)

by ASA similarity

△ABD ≅ △CBD

Hence proved !