Diagonal of a parallelogram intersect each other at point o if AO =5,No=12and AB =13 then show that a CD is a rhombus
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5, 12 and 13 form a Pythagorean triplet. Thus, Δ AOB is a right angle triangle, right angled at O. ... Thus, in parallelogram ABCD, diagonals bisect at right angles. Hence, ABCD is a rhombus.
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