Question

Diagonal of a rectangular field is 17m and perimeter is 46 m find its area​

Answer 1

Answer:

hope it helps you see the attachment for further information

Answer 2

The area of the rectangle is 120 m².

Step-by-step explanation:

Consider the provided information.

It is given that the perimeter of the rectangle is 46 m.

let the length of the rectangle is l and and breadth is b.

The perimeter of the rectangle is: $P=2(l+b)$  

Substitute the respective values in the above formula.

$46=2(l+b)$  

$l+b=23$  

Now squaring both the sides.

$(l+b)^2=23^2$  

$l^2+b^2+2lb=529$ ......(1)

It is given that the diagonal of the rectangular field is 17 m.

By using the Pythagorean theorem:

l²+b² = 17²

l²+b² = 289

Substitute the value of l²+b² in equation 1.

$289+2lb=529$

$2lb=240$

$lb=120$

As we know area of rectangle is: $A=lb$

Therefore, the area of the rectangle is 120 m².

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