Question

Diagonal of a rhombus are of length 6m and 8m find the perimeter of the rhombus

Answer 1

Step-by-step explanation:

let diagonal DB be 6m and AC be 8m

so we have ,

OA = OC = 4m ( diagonal of rhombus bisect each other )

OD = OB = 3m. { diagonal of rhombus bisect each other )

In∆ DOC

angle DOC = 90° ( Diagonal of rhombus bisect each other at 90 degree )

so applying Pythagoras theorem,

DC² = OD² + OC²

DC² = ( 3 ) ² + ( 4 )²

DC² = 9 + 16

DC² = 25

DC= 5m

Now

since all side of rhombus are equal so ,

its perimeter will be,

4 × side = 4 × 5 = 20m.

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