diagonal of a square is 2.8 CM then its area is
Answers
Answered by
5
Solution :-
Given - Length of a diagonal of a square = 2.8 cm
Area of square = d²/2
⇒ (2.8)²/2
⇒ 7.84/2
⇒ 3.92 cm²
So, the area of the given square is 3.92 cm²
Answer.
Given - Length of a diagonal of a square = 2.8 cm
Area of square = d²/2
⇒ (2.8)²/2
⇒ 7.84/2
⇒ 3.92 cm²
So, the area of the given square is 3.92 cm²
Answer.
Answered by
3
Let the length of a side of a square= a cm
Length of a square diagonal(d)= √2a
d= √2 a
Diagonal of a square= 2.8 cm ( given)
2.8 = √2 × a
a= 2.8 /√2 cm
Area of square= side×side = a²
Area of square= (2.8 /√2)²
Area of square= (2.8 /√2)(2.8 /√2)
Area of square= (2.8× 2.8) / (√2×√2)
Area of square= (2.8× 2.8) / 2= 1.4 × 2.8 = 3.92 cm²
Hence, the area of square is 3.92 m²
Length of a square diagonal(d)= √2a
d= √2 a
Diagonal of a square= 2.8 cm ( given)
2.8 = √2 × a
a= 2.8 /√2 cm
Area of square= side×side = a²
Area of square= (2.8 /√2)²
Area of square= (2.8 /√2)(2.8 /√2)
Area of square= (2.8× 2.8) / (√2×√2)
Area of square= (2.8× 2.8) / 2= 1.4 × 2.8 = 3.92 cm²
Hence, the area of square is 3.92 m²
Similar questions