Question

Diagonal of a square is 4√2 cm. Find the diagonal of a square whose area is twice its area.​

Answer 1

Answer:

8 cm

Step-by-step explanation:

diagonal of a square = side * √2 = 4√2 cm (given)

Therefore, side of square = diagonal/ √2 = 4√2/√2 = 4 cm

Area of this square = side*side = 4*4 = 16 sq. cm

Area of other square = 2*area of previous square = 2*16 = 32 sq. cm

Therefore side of this square = √area = √32 = √(2*2*2*2*2) = 4√2 cm

Thus, the diagonal of this new square = 4√2*√2 = 4*2 = 8 cm

Hope it helps.