Question

Diagonal of square = 4√2 , side = ?

Answer 1

$diagonal = 4 \sqrt{2} cm \ \\ let \: each \: side \: be \: a \\ then \\ \sqrt{a {}^{2} +a {}^{2} } = 4 \sqrt{2} \\ ( \sqrt{2a {}^{2} } ) {}^{2} = (4 \sqrt{2} ) {}^{2} ......squaring \: both \: sides \\ 2a {}^{2} = 32 \\ a {}^{2} = 32 \div 2 \\ a {}^{2} = 16 \\ a = \sqrt{16} \\ a = 4cm$

Answer 2

Hiiii,
the diagonal of square =4 ×under Square root 2
the sides of square=a
2a square=32
side=2×under Square root 2