Question

diagonal of the room=

Answer 1

------------------------------------HEY DEAR------------------------------

HERE IS YOUR ANSWER...........

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DIAGONAL OF CUBE =  ROOT 3 *SIDE

PROOF: We know that each cube is made of 6 faces and each face has 4 edges. So first of all derive the face diagonal, from figure consider the face BCDE, and draw a line from D to B due to this BCDE is divided into two triangle, triangle BCD and triangle BDE, and DB is called diagonal, and we have to find out the length of this diagonal. We can see that both Triangles are right angled so we can apply pythagoras theorem on both triangles, from we can find DB, consider the triangle BCD, by applying theorem in this triangle,

DB2 = DC2 + CB2,

Length of DC = CB = a,

So DB2 = a2 + a2 => DB2 = 2a2,

DB = face diagonal = 2 a ------equation 1,

Now to find the space diagonal draw a line from a to d and apply Pythagoras theorem on Right Triangle ADB,

So, AB2 = AD2 + DB2, value of AD = a and DB = √(2) a according to …...........equation 2,

AB2 = a2 + (√2a)2,

= √3.a.

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HOPE IT HELPS YOU..

THANKS..

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Answer 2

[\] [/] I think their are two diagonals