diagonal PR and QS of a quadrilateral PQRS intersect each other at O. show that as PSO ×QOR= POQ×SOR
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Answer:
Draw SN⊥PR and QN⊥PR.
therefore, area ΔPSA×areaΔQAR=
= (1)
Also, area ΔSAR×areaΔPAQ=
= (2)
Now, from equation (1) and (2), we get
area ΔPSA×areaΔQAR=area ΔSAR×areaΔPAQ
Hence proved.
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