Diagonal PR and QS of a rhombus PQRS are 20 cm and 48 cm respectively. Find the the length of side PQ.
Answers
Answered by
30
Hey!!mate Ur answer
By the formula:
Square root (d/2^2+d/2^2)
= square root ( 20/2^2+48/2^2)
= root 10^2+24^2
= root 100+576
=root 676
= 26 cm
hence, side of rhombus is 26 cm
By the formula:
Square root (d/2^2+d/2^2)
= square root ( 20/2^2+48/2^2)
= root 10^2+24^2
= root 100+576
=root 676
= 26 cm
hence, side of rhombus is 26 cm
Answered by
72
Hi friend ✋✋✋✋
---------------
Your answer
-------------------
Measure of diagonal PR and QS of a rhombus PQRS = 20 cm and 48 cm
Now,
---------
We know that,
Diagonals of a rhombus bisect each other at right angles.
Then,
---------
Let the measure of each side of the rhombus be x.
So,
-----
By Pythagoras theorem ,
--------------------------------------
(x)² = (20/2)² + (48/2)²
=> x² = (10)² + (24)²
=> x² = 100 + 576
=> x² = 676
=> x = √676
=> x = 26 cm
Therefore, measure of each side of the rhombus is 26 cm.
HOPE IT HELPS
---------------
Your answer
-------------------
Measure of diagonal PR and QS of a rhombus PQRS = 20 cm and 48 cm
Now,
---------
We know that,
Diagonals of a rhombus bisect each other at right angles.
Then,
---------
Let the measure of each side of the rhombus be x.
So,
-----
By Pythagoras theorem ,
--------------------------------------
(x)² = (20/2)² + (48/2)²
=> x² = (10)² + (24)²
=> x² = 100 + 576
=> x² = 676
=> x = √676
=> x = 26 cm
Therefore, measure of each side of the rhombus is 26 cm.
HOPE IT HELPS
Similar questions