Diagonal QS of a paralalleogram PQRS bisect angle Q, show that, 1.if bisect angle S 2.PQRS is rhombus
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PQRS is a parallelogram where PR and QS are diagonals intersect at point O
In △POS and △ROQ
⇒ ∠SPO=∠QRO [ Alternate angles between parallel lines are equal ]
⇒ ∠PSO=∠RQO [ Alternate angles between parallel lines are equal ]
⇒ ∠POS=∠ROQ [ Vertically opposite angles ]
∴ △POS≅△ROQ [ By AAA congruence theorem ]
⇒ segPO≅segRO [ By CPCT ]
⇒ segSO≅segQO [ By CPCT ]
Step-by-step explanation:
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