Question

diagonals ac and bd of a parallelogram abcd intersect at o .given that an = 12cm and perpendicular distance between ab and dc is 6 cm .calculate the area of triangle aod

Answer 1

AO=6cm
DO=3cm
area of ∆=1/2×base×height
=1/2×3cm×6cm
=3cm×3cm
=9 sq. cm

Answer 2

Answer:

Take AB as 12 cm

Take BC as 6 cm

Since : Area of parallelogram = Base×Height = (12×6) cm²

= 72 cm²

Now

Area of Triangle AOD = 1/4 × Area of Parallelogram

1/4× 72 = 18 cm²