Diagonals ac and bd of a quadrilateral abcd intersect at o in such a way that oa: oc = 3:2 is abcd a parallelogram?
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Answer:
No quadilateral ABCD is not a parallelogram.
The reason behind it is that it is the property of parallelogram that *diagonls are bisected by each other*
It means,
AO=OC
but here given AO:OC = 3:2
So ABCD is not a parallelogram.
Step-by-step explanation:
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Step-by-step explanation:
Dev01 ABCD is not a parallelogram, because diagonals of a parallelogram bisect each other. Here OA ≠ OC..
Hope its help..
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