Diagonals AC and BD of A quadrilateral ABCD intersect at O in such way that ar(AOD) =ar (BOC) prove that ABCD is A trapezium.
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ar AOD=ar BOC(given)
Add Ar(AOB) in both sides.
Ar (ABD)=Ar (ABC)
these two triangles lie on same base AB nd have equal area so they will lie between same parallel lines.
thus AB is parallel To CD nd hp that ABCD with AB parallel to CD becomes a trapezium.make me brainlist.
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cuttie77:
ohk wait sis
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