Diagonals AC and BD of a trapezium ABCD with AB II DC intersect each ot
Prove that ar (AOD) = ar (BOC).
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Step-by-step explanation:
Since ABD and ABC are on the same base AB and between the same parallels AB and DC
ar (ABD) = ar (ABC)
ar (ABD) - ar (ABO) = ar (ABC) - ar (ABO)
ar (AOD) = ar (BOC)
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