Question

diagonals AC and BD of a trapezium ABCD with AB parallel to DC intersect each other at O.prove that ar(AOD)=ar(BOC)​

Answer 1

Answer:

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Answer 2

$\huge{\underline{\bf\orange{Answer :-}}}$

Given:

ABCD is Trapezium with AB||DC.

To Find:

ar(AOD) =ar((BOC)

Solution:

it can be observed that ∆DAC and ∆DBC lie on the same base DC and between same parallels AB and CD.

∴ ar(∆DAC) = ar(∆DBC)

Subtract Area (ΔDOC) from both side.

$\huge\fcolorbox{aqua}{lime}{HENCE PROVED\:}$