Question

Diagonals AC and BD of parallelogram ABCD intersect at 0.
If angle BOC = 90° and angle BDC = 50°, find angle
OAB.

plesśe answer​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanatiON

IN TRIANGLE (DOC)

ANGLE CDO =50

ANGLE DOC =90

ANGLE DCO = 180 - (90 + 50)

                        =  180 - 140

                          =  40 DIGREE.

ANGLE DCO = ANGLE OAB    ( ALTERNATE INTERIOR ANGLE )

      40           =      ANGLE OAB