Diagonals AC and BD of parallelogram ABCD intersect at O. If ∠BOC =
90° and ∠BDC = 50°, find ∠OAB.
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It is given that angle BOC = 90.
It means the diagonals cut each other at right angle.
Angle AOB= 180- Angle BOC =90
So, angle AOB = angle BOC = 90.
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