Question

Diagonals AC and BD of trapezium ABCD with AB||DC intersect each other at O. prove that ar(AOD) = ar (BOC)?

Answer 1

abcd is a trapezium andAB and BD intersect at O..such that Two triangles will obtained named Aoc nd Boc..then congruent both traingles thus u get in cpct ar(AOC )= AR(BOC)..hope this will help you...thank you

Answer 2

Solution:

GivEn:

• △DAC and △DBC lie on the same base DC and between the same parallels AB and CD.
• Ar(△DAC) = ar(△DBC)

⇒ ar(△DAC) – ar(△DOC) = ar(△DBC) – ar(△DOC)

⇒ ar(△AOD) = ar(△BOC)

Thanks