Math, asked by radhikaabc00, 19 hours ago

diagonals AC of a parallelogram ABCD bisects angle A show that (i) its bisect angle C also, (ii) ABCD is a rhombus​

Answers

Answered by ashapatel83
1

Answer:

The diagonal AC of a parallelogram ABCD bisects ∠A. We can use alternate interior angles property to show that the diagonal AC bisects ∠C and by showing all sides are equal, it can be proved ABCD is a rhombus. ... Hence, ABCD is a rhombus.

Step-by-step explanation:

Hopes ot help u dear

Answered by nightx392
1

Answer:

my dear friend your answer is

Step-by-step explanation:

Given: The diagonal AC of a parallelogram ABCD bisects ∠A. We can use alternate interior angles property to show that the diagonal AC bisects ∠C and by showing all sides are equal, it can be proved ABCD is a rhombus. ... Hence, ABCD is a rhombus

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