diagonals AC of a parallelogram ABCD bisects angle A show that (i) its bisect angle C also, (ii) ABCD is a rhombus
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The diagonal AC of a parallelogram ABCD bisects ∠A. We can use alternate interior angles property to show that the diagonal AC bisects ∠C and by showing all sides are equal, it can be proved ABCD is a rhombus. ... Hence, ABCD is a rhombus.
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my dear friend your answer is
Step-by-step explanation:
Given: The diagonal AC of a parallelogram ABCD bisects ∠A. We can use alternate interior angles property to show that the diagonal AC bisects ∠C and by showing all sides are equal, it can be proved ABCD is a rhombus. ... Hence, ABCD is a rhombus
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