Question

Diagonals of a cube is √6 cm, then find its lateral surface area.

Answer 1

Answer:

= 8cm^2

Step-by-step explanation:

Diagonal of square = $\sqrt{3} a$

So, $\sqrt{6} =\sqrt{3}a$

=$(\sqrt{6} )^{2} =( \sqrt{3} a)^{2}$

= $6=3a^{2}$

= $\frac{6}{3} = a^{2}$

= $2=a^{2}$

= $\sqrt{2}^{2} = \sqrt{a^{2} }$

= √2=a

hence the side = √2

L.S.A= $4a^{2}$

= $4*\sqrt{ 2}^{2}$

= 4*2

= 8cm^2

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