Question

diagonals of a parallelogram ABCD intersect at O if angle AOB = 90° and angle BCD = 40° then angle OAB is _______​

Answer 1

Answer:

1 Answer. Its given ABCD is a IIgram and AC and BD are its diagonals intersecting at point O. so, therefore angle OAB = 400.

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Answer 2

Answer:

Step-by-step explanation:

Given : angle BOC = 900  

                           angle BDC = 500  

         To find : angle OAB  

         Answer : i) angle BOC + angle COD = 1800 (Linear Pair)

                          angle COD = 1800 - angle BOC

                          angle COD = 1800 - 900  

                          angle COD = 900

                      ii) angle COD + angle ODC + angle OCD = 180 (Angle Sum Property)

                          angle OCD = 180 - 90 - 50

                          angle OCD = 400

                      iii) angle OCD = angle OAB (Alternate Interior Angles)

                           so, therefore angle OAB = 400.