Diagonals of a quadrilateral are of lengths 10cm and 24cm. If the diagonals bisect each other
at right angles, find the length of each side of the quadrilateral. What special name can you give
to this quadrilateral ?
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Answer:
Let ABCD be the rhombus where, AC=10cm and BD=24cm
Let AC and BD intersect each other at O.Now, diagonals of rhombus bisect each other at right angles.
Thus, we have
AO=
2
1
×AC=
2
1
×10=5cm and
BO=
2
1
×BD=
2
1
×24=12cm
In right angled △AOB,
⇒ (AB)
2
=(AO)
2
+(BO)
2
⇒ (AB)
2
=(5)
2
+(12)
2
⇒ (AB)
2
=25+144
⇒ (AB)
2
=169
∴ AB=13cm
∴ The length of each side of rhombus is 13cm.
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