Question

diagonals of a rectangle ABCD intersect at O if angle BOC is equal to 70 find angle ODA

Answer 1

Angle ODA is 55when diagonals of rectangle intersect at o and angle BOC is 70

Answer 2

angle boc=aod[vertically opposite angles]
aod=70 ,since digonals of rectangle abcd insecr at o there fore oa=ob=oc=od ,aod is an iscoless triangle oad=ada [ angles opposite to equal sides of triangle r equal ] let oad=oda=x
oad+oda+aod=180
x+x+70=180
2x=180-70
2x=110
x=55