diagonals of a rectangle ABCD intersect at point ko if AC is equals to 8 cm then find the length of the and if angle C is equals to 35 degree then find the measure of angle acb
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Answer:
Solution= 35 degree
Step-by-step explanation:
Diagonals of a rectangle are congruent.
So, AC= BD= 8cm
Also, rectangle is a parallelogram so, the diagonals bisect each other
Thus, BO=OD=4 cm
Now, AD || CB
So , angle CAD= ANGLE ACB = 35 degree
(Since , alternate interior angles are equal)
Hope this helps
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