Diagonals of a rectangle ABCD intersect at point O. if AC=8cm then find BO and if <CAD=35° then find <ACB
Answers
Answered by
4
Answer:
BO=4 cm,<ACB=35°
Explanation:
- Diagonals of rectangle are congurent(equal)
- So,AB=BD=8cm
- (BO is half of BD)BO=8÷2=4
- <ACB=<CAD by alternate interior angle
Hope it will help you
Answered by
1
Answer:
Diagonals of a rectangle are congruent.
So, AC=BD=8 cm
Also, rectangle is a parallelogram so, the diagonals bisect each other.
Thus, BO=OD=4 cm
Now, AD∣∣CB
So, ∠CAD=∠ACB=35
o
(Since, alternate interior angles are equal)
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