Chemistry, asked by harshitfree090, 6 months ago

Diagonals of a rectangle ABCD intersect at point O. if AC=8cm then find BO and if <CAD=35° then find <ACB​

Answers

Answered by 4734nikita
4

Answer:

BO=4 cm,<ACB=35°

Explanation:

  • Diagonals of rectangle are congurent(equal)
  • So,AB=BD=8cm
  • (BO is half of BD)BO=8÷2=4

  • <ACB=<CAD by alternate interior angle

Hope it will help you

Answered by BELIEVES
1

Answer:

Diagonals of a rectangle are congruent.

So, AC=BD=8 cm

Also, rectangle is a parallelogram so, the diagonals bisect each other.

Thus, BO=OD=4 cm

Now, AD∣∣CB

So, ∠CAD=∠ACB=35

o

(Since, alternate interior angles are equal)

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