Math, asked by siya856, 1 year ago

diagonals of a rectangle ABCD intersect at point o. lf AC=8 cm then find BO and if <CAD =35° then find <ACB

Answers

Answered by khan9757

measure of, < ACB is90 degree

siya856: but why 90°

khan9757: because the measure of all angel of a rectangle is 90 degree

siya856: ok thanks

siya856: ple or ek question ka answer bataoge

Answered by XxArmyGirlxX

Diagonals of a rectangle are congruent.

So, AC=BD=8 cm

Also, rectangle is a parallelogram so, the diagonals bisect each other.

Thus, BO=OD=4 cm

Now, AD∣∣CB

So, ∠CAD=∠ACB=35⁰

(Since, alternate interior angles are equal)

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