Math, asked by Yatj, 1 year ago

Diagonals of a rhombus ABCD intersect at O .Prove that OA^2+OC^2=2AD^2-BD^2/2

Answers

Answered by Aditi1107

1

Instead of 2AD^2, it should be AD^2/2

Yatj: but the question is right

Aditi1107: I am sure it is not... cz solving it the other way which I told will give you the answer

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