Question

diagonals of a rhombus are 18cm and 24cm find side of the rhombus

Answer 1

$the \: diagnols \: of \: a \: rhombus \: bisect \\ each \: other \: at \: {90}^{0} . \\ so \: let \: whole \: diagonal = a \\ therefore \\ {a}^{2} + {a}^{2} = {side}^{2} \\ so \: {9}^{2} + {12}^{2} = {x }^{2} \\ 81 + 144 = {x}^{2} \\ 225 = {x}^{2} \\ so \: x = 12$

Answer 2

Step-by-step explanation:

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