Question

diagonals of a rhombus are 20CM and 21cm respectively, then find the side of rhombus and it's perimeter ​

Answer 1

Answer:

Step-by-step explanation:

We know that in a rhombus the diagonals bisect each other at 90

so let AC=20 AND BD=21 CM

AD=10 AND BO=10.5 CM

AB^2=AD^2+OB^2

=10^2+10.5^2

=100+110.25

=210.25

AB=14.5 IS THE SIDE OF THE RHOMBUS

PRIMETER=4S

=4(14.5)

=58 CM

Hope its help!!

Answer 2

Answer:

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The answer is 210

Step-by-step explanation:

perimeter of rhombus =1/2×20×21

=10×21

=210cm