Question

Diagonals of a rhombus are 24cm and 10cm find its area and perimeter

Answer 1

let the diagonals be.....
diagonal 1=p=24cm
diagonal 2=q=10cm
area of the rhombus = pq/2
= 24x10/2
= 120cm^2
each side of the rhombus= p/4
= 24/4=6cm
perimeter of the rhombus = 4xside
= 4x6=24cm

Answer 2

area of rhombus =1/2× product of diagonals
area of rhombus =1/2× 24×10=120
perimeter of rhombus ,
let ABCD be a rhombus
since diagonals of rhombus bisect at 90 deg
let diagonals bisect at O
in triangle AOB is right angle triangle (of rhombus ABCD)
by Pythagoras theorem =
OB ^2 +OA ^2=AB^2
OB=BD/2=24/2=12 cm
OA= AC/2=10/2=5cm
THEREFORE
AB^2 = 12^2 + 5^2
AB = √ 144+25
= √ 169
= 13
AB =13 cm
since all sides of rhombus are equal so perimeter of it = 13×4 cm= 52 cm