Diagonals of a rhombus are 48cm and 14cm find the perimeter
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Hey there!
Given,
D₁ = 48 cm
D₂ = 14 cm
OA = 1/2 * D₁ = 1/2 * 48 = 24 cm
OB = 1/2* D₂ = 1/2 * 14 = 7 cm
Now,
From Pythagoras theorem,
AB² = OA² + OB²
AB² = (24)² + 7²
AB = √(576 + 49)
AB = √625
AB = 25 cm
Now,
Perimeter of Rhombus = side² = AB² = (25)² = 625 m
Hope It Helps You!
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