Question

Diagonals of a rhombus are of length 16cm and 12cm. Find its perimeter.

Answer 1

$<b>perimeter of rhombus =$
$2 \sqrt{ {16}^{2} } + \sqrt {12}^{2} = 40 \: cm$

Answer 2

area of rhombus =

$\frac{1}{2 } \times d1 \times d2 \\ \frac{1}{2} \times 16 \times 14 \\ 16 \times 7 \\ 112 \\ \\ perimeter \: ofrohmbus = 4 \times 112 \\ = 448$

ans=448