diagonals of a rhombus measure 4cm and 10cm find its perimeter
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Diagonals of the rhombus 10,24 cm
since the diagonals meet at the center of the rhombus,
they create 4 right angles in the center.
so in this, we can use the Pythagoras theorem, which
states that the sum of squares on the height and
the base of a right angle is equal is square on the
hypotenuse.
Length of the base =
10/2 =5 cm
Length of the height = 24/2=12 cm.
By Pythagoras theorem,
Hypotenuse=(5) ^2 +(12) ^2
(AB) ^2=25+144
(AB) ^2 m=169 ^2
=AB= √(13) ^2
∴ Hypotenuse =13 cm
So, the side of a rhombus is 13 cm.
the perimeter of the rhombus =4×side
=4×13
=52 cm
Therefore, the perimeter of the rhombus is 52 cm.
Step-by-step explanation:
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