Question

Diagonals of a rhombusar а 20 cm and 21 cm respectively , then find the side of chombus its perimeter and ​

Answer 1

Answer:

side of Rhombus = 29, its perimeter = 116 cm

Step-by-step explanation:

 Given diagonals of Rhombus d₁ = 20  d₂=21 cm

  the relation between side and diagonals in Rhombus

                                       $a^{2}$=  $d_{1}^{2}$+$d_{2}^{2}$

                                       $a^{2} = 20^{2} +21^{2}$

                                       $a^{2} = 400 +441$

                                       $a^{2} =841$

                                      $a= \sqrt{841}$= 29

side of Rhombus a= 29 cm

perimeter of Rhombus = 4a = 4 (29)        

                                               = 116 cm