Question

Diagonals of rectangle ABCD intersect at O.If angle AOB = 30°, find angle COD angle OCD.

Answer 1

HEY MATE.....

Angle AOB = 30°
So, Angle COD = 30° (Vertically Opposite Angles)
Now, Angle OCD = Angle ODC (Since OC = OD)
Let Angle OCD = Angle OCD = x
Do, Angles
COD + OCD + ODC = 180° (Angle-sum property)
=) 30°+ x + x = 180°
=) 30°+ 2x = 180°
=) 2x = 180° - 30°
=) 2x = 150°
Therefore, x = Angle OCD = 150°÷2 = 75°

HOPE IT HELPS.....

Answer 2

Answer:

angle COD=30° And angle OCD=75°

Step-by-step explanation:

angle AOB=30°

angle COD=30°{vertically opposite angels}

now, angle OCD=angle ODC (OC=OD)

Let angle OCD and ODC be x

according to question:-

= COD+OCD+ODC=180°(angle sum property)

= 30°+x+x= 180°

= 30°+2x=180°

= 2x= 180°-30°=150°

= x= 150/2 = 75°

thanks for asking