Diagonals of rhombus are 16cm and 12cm.Find.The perimeter
Answers
Answered by
2
Answer:
40 cm.
Step-by-step explanation:
- Side of rhombus = √ (16/2)² + (12/2)²
= √ 8² + 6² = √ 10² = 10 cm.
- Perimeter = 4 s = 4 x 10 = 40 cm.
thank u.
Answered by
2
hey.
Let side of a rhombus be a.
=) a² = (d1/2)² + (d2/2)²
(by Pythagoras theorem)
=) a² = (16/2)² + (12/2)²
= 8² + 6²
= 64 +36 = 100
=) a = 10cm
Since Perimeter of a rhombus = 4*a
= 4*10
= 40cm.
hope it helps you!!
Let side of a rhombus be a.
=) a² = (d1/2)² + (d2/2)²
(by Pythagoras theorem)
=) a² = (16/2)² + (12/2)²
= 8² + 6²
= 64 +36 = 100
=) a = 10cm
Since Perimeter of a rhombus = 4*a
= 4*10
= 40cm.
hope it helps you!!
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