Question

Diagonals of rhombus is 10 and area is 90 find perimeter

Answer 1

hope it will help you

Answer 2

Answer:

Step-by-step explanation:

Area of a rhombus =pq÷2

where p and q are its diagonal.

So,90=10×q÷2

90×2=10q

90×2÷10=q

18=q

In rhombus the diagonals are perpendicular director to each other.So it forms a right angle triangle.

By using Pythagoras theorem,we get,

(X)^2= (5)^2+9^2

X^2=25+8

X^2=106

X=√106