Question

diagonals PR and QS of a rhombus pqrs are 20 cm and 48 CM respectively find the length of the side PQ

Answer 1

The diagonals bisect each other at right angles. So by Pythagoras Theorem, we concluded :-

a² = (x/2)² + (y/2)²

Where a is the side and x and y are the two diagonals.
So let's substitute the value.

=> a² = (20/2)² + (48/2)²

=> a² = (10)² + (24)²

=> a² = 100 + 576

=> a² = 676

=> a = √676

=> a = 26 cm


Answer :- 26 cm

Answer 2

$\bf\huge\boxed{\boxed{\:Content\:Quality}}}$

Use this formula:  

= $\bf\huge\sqrt{\frac{d}{(2)^{2} } } + \sqrt\bf\huge\frac{d}{(2)^{2} }$

= $\bf\huge\sqrt{\frac{(20}{(2})^{2} + \frac{(48}{(2})^{2}$

= $\bf\huge\sqrt{(10)^{2}+(24)^{2}}$

= $\bf\huge\sqrt{100 + 576}$

=$\bf\huge\sqrt{676}$

= 26 cm

$\bf\huge\boxed{\boxed{\:Side\:of\:rhombus\:=\:26\:cm}}}$

$\bf\huge\boxed{\boxed{\boxed{\:Radhe\:Radhe}}}$