Question

Diagonals pr and sq of a quadrilateral pqrs meet in o. Prove that pq + qr + rs + sp > pr + qs

Answer 1

Answer:

Each diagonal is greater the two sides side of triangles formed by 2 adjacent sides of quadrilateral because 2 sides of a triangle are always greater than the third side.

Step-by-step explanation:

So the sum of 2 diagonals are together greater than 4 sides of quadrilateral.